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Question

Q. If xsin θcos θ-sin θ-x1cos θ1x= 8, write the value of x.

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Solution

xsin θcos θ-sin θ-x1cos θ1x=8Expand along R1x-x2-1-sin θ-xsin θ-cos θ+cos θ-sin θ+xcos θ=8-x3-x+x sin2 θ+sin θ cos θ-sin θ cos θ+x cos2 θ=8-x3-x+x sin2 θ+ cos2 θ=8-x3-x+x =8-x3=8x3=-8x=-2

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