Solve -160-using -160-BODMAS100 -215-10-400 -247-100-50-5 -215-10 -215-105-14 -247-7-6 -215-5 -215-1 -215-4

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Byju's Answer

Standard IX

Mathematics

Conditional Identities

Solve #160;...

Question

$S o l v e u \sin g B O D M A S 100 \times (- 10) + [400 \div \{100 - (50 - 5 \times 10 \times 10)\}] 5 + [14 \div (- 7) - \{6 \times (5 \times 1 \times 4)\}]$

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Solution

$Hi, Here we are providing you the solution to the first part . 100 \times (- 10) + [400 \div \{100 - (50 - 5 \times 10 \times 10)\}] = - 1000 + [400 \div \{100 - (50 - 50 \times 10)\}] = - 1000 + [400 \div \{100 - (50 - 500)\}] = - 1000 + [400 \div \{100 - (- 450)\}] = - 1000 + [400 \div \{100 + 450\}] = - 1000 + [400 \div 550] = - 1000 + \frac{400}{550} = - 1000 + 0.72 = - 999.28$
Similarly try second part

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Similar questions

Add using number line:

(1) 5 and 3

(2) 6 and 2

(3) (−3) and (+5)

(4) 8 and (−12)

(5) (−7) and 5

(6) 10 and (−14)

(7) (−5) and (−2)

(8) (+6) and (−9)

(9) (−4) and (−1)

(10) 1 and (−5)

Solving $100 \times 7 + 10 \times 5 + 6$ gives ___ .

Q. Observe the pattern and fill in the blanks.
2

\times

200 = 400 2

\times

300 = 600 2

\times

400 = 800
3

\times

200 = 600 3

\times

300 = 900 3

\times

400 = 1200
4

\times

200 = 800 4

\times

300 = 1200 4

\times

400 = 1600
5

\times

200 = 1000 5

\times

300 = 1500 5

\times

400 = 2000
6

\times

200 =____ 6

\times

300 =____ 6

\times

400 =____
7

\times

200 =____ 7

\times

300 =____ 7

\times

400 =____
8

\times

200 =____ 8

\times

300 =____ 8

\times

400 =____
9

\times

200 =____ 9

\times

300 =____ 9

\times

400 =____
10

\times

200 =____ 10

\times

300 =____ 10

\times

400 =____
11

\times

200 =____ 11

\times

300 =____ 11

\times

400 =____
14

\times

200 =____ 14

\times

300 =____ 14

\times

400 =____
15

\times

200 =____ 15

\times

300 =____ 15

\times

400 =____
25

\times

200 =____ 25

\times

300 =____ 25

\times

400 =____
27

\times

200 =____ 27

\times

300 =____ 27

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400 =____
39

\times

200 =____ 39

\times

300 =____ 39

\times

400 =____
48

\times

200 =____ 48

\times

300 =____ 48

\times

400 =____
50

\times

200 =____ 50

\times

300 =____ 50

\times

400 =____

Q. Solve the system of linear equations in three variables
5x = 2y
7y = 5z
4x + 5y + 6z = 150

The general form of 456 is

A. (4 × 100) + (5 × 10) + (6 × 1)

B. (4 × 100) + (6 × 10) + (5 × 1)

C. (5 × 100) + (4 × 10) + (6 × 1)

D. (6 × 100) + (5 × 10) + (4 × 1)

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Solve using BODMAS100×-10+400÷100-50-5×10×105+14÷-7-6×5×1×4

Hi, Here we are providing you the solution to the first part. 100×-10+400÷100-50-5×10×10=-1000+400÷100-50-50×10=-1000+400÷100-50-500=-1000+400÷100--450=-1000+400÷100+450= -1000+400÷550= -1000+400550= -1000+0.72= -999.28 Similarly try second part

$S o l v e u \sin g B O D M A S 100 \times (- 10) + [400 \div \{100 - (50 - 5 \times 10 \times 10)\}] 5 + [14 \div (- 7) - \{6 \times (5 \times 1 \times 4)\}]$