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Dear Student, Molar mass of Sulphur trioxide = 32 + 3 x 16 = 80 g/mol Number of grams of O in 80 g nbsp;SO3 nbsp;= 48 g nbsp;Number of grams of oxyg ...

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Byju's Answer

Standard X

Chemistry

Avogadro's Number

The #160;nu...

Question

$T h e n u m b e r o f o x y g e n a t o m s i n 20 g r a m s o f s u l p h u r t r i o x i d e i s t h e s a m e a s t h o s e p r e s e n t i n X g r a m s o f o z o n e . T h e a t o m i c m a s s o f s u l p h u r a n d o x y g e n a r e 32 u a n d 16 u r e s p e c t i v e l y . F i n d t h e v a l u e o f x .$

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Solution

Dear Student,

Molar mass of Sulphur trioxide = 32 + 3 x 16 = 80 g/mol
Number of grams of O in 80 g SO₃ = 48 g
Number of grams of oxygen in 20 g SO₃ = (48/80) x 20
= 12 g
Number of moles in 12 g oxygen = 12/16 = 0.75
Number of atoms in 0.75 moles of oxygen
= 0.75 x 6.02 x 10²³
= 4.515 x 10²³
Molar mass of ozone, O₃ = 3 x 16 = 48 g
6. 02 x 10²³ atoms make 48 g ozone
4.515 x 10²³ atoms make (48 / 6.02 x 10²³) x 4.515 x 10²³= 36 g ozone.

Hence, the value of X is 36g

Regards,

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The number of oxygen atoms in 20 grams of sulphur trioxide is the same as those present in X grams of ozone . The atomic mass of sulphur and oxygen are 32 u and 16 u respectively. Find the value of x.