wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The function f(x)=sinlogx+x2+1, is(1) An even function(2) An odd function(3) A periodic function(4) Neither odd nor even function

Open in App
Solution

fx=sinlogx+x2+1Let gx=logx+x2+1g-x=log-x+-x2+1g-x=log-x+x2+1g-x=logx2+1-x×x2+1+xx2+1+xg-x=logx2+12-x2x2+1+xg-x=logx2+1-x2x2+1+xg-x=log1x2+1+xUse logamn=logam-logang-x=log 1-log x2+1+xg-x=-log x2+1+xg-x=-gxNowfx=sinlogx+x2+1fx=singxf-x=sing-x=sin-gx=-singx=-fxHence fx is odd

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon