Question

$$\begin{gathered} When{10}^{20}electronsareremovedfromthesurfaceofaneutralmetalplate,theelectricchargeonit(incolumb)is \\ \left(a\right)+1.6 \\ \left(b\right)-1.6 \\ \left(c\right){10}^{-19} \\ \left(d\right){10}^{19} \end{gathered}$$

Answer 1

Dear Student

Charge on one electron is

$$\begin{gathered} e=1.6021\times {10}^{-19}C \\ Numberofelectronslost=\frac{Totalchargeonmetalplate}{Chargeononeelectron} \\ Totalchargeonmetalplate=Chargeononeelectron\times Numberofelectronslost \\ Totalchargeonmetalplate=1.6021\times {10}^{-19}C\times {10}^{20} \\ Totalchargeonmetalplate=+16.0C \end{gathered}$$

As electrons are lost so total charge on metal plate is positive.