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Question

1. limx0sin(π cos2(tan(sin x)))x2is equal to :(a)π (b) π4(c) π2 (d) None of these

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Solution

limx0sinπ cos2tan sin xx2We know sin θ=sin π-θlimx0sinπ cos2tan sin xx2=limx0sinπ-π cos2tan sin xx2=limx0sinπ1-cos2tan sin xx2Use 1-cos2θ=sin2θ=limx0sinπsin2tan sin xx2=limx0sinπ sin2tan sin xx2×π sin2tan sin xπ sin2tan sin x=limx0sinπ sin2tan sin xπ sin2tan sin x×π sin2tan sin xx2=limx0sinπ sin2tan sin xπ sin2tan sin x×limx0π sin2tan sin xx2=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0sin2tan sin xx2=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sin2tan sin xx2×tan2 sin x×tan2 sin x=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sin2tan sin xtan2 sin x×tan2 sin xx2=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sin2tan sin xtan2 sin x×limx0 tan2 sin xx2=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sintan sin xtan sin x2×limx0 tan2 sin xx2×sin2x×sin2x=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sintan sin xtan sin x2×limx0 tan2 sin xsin2x×limx0sin2xx2=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sintan sin xtan sin x2×limx0 tan sin xsin x2×limx0sinxx2=limx0sinπ sin2tan sin xπ sin2tan sin x×π ×limx0 sintan sin xtan sin x2× limx0tan sin xsin x2×limx0sinxx2Use limθ0sinθθ=1 and limθ0tanθθ=1=1×π ×1× 1×1=π

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