Lim- x - 0cosx-2cosx-22cosx-23-cosx-2n is equal to

The correct option is A 1 the given question turns in = lim_x→0sin x2^nsin2^ n x #160; #160; #160; #160; #160; #160; #160; #1 ...

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Standard XII

Mathematics

Substitution Method to Remove Indeterminate Form

limδ x → 0cos...

Question

$lim δ x \to 0 cos \frac{x}{2} cos \frac{x}{2^{2}} cos \frac{x}{2^{3}} . . . . . . cos \frac{x}{2^{n}}$ is equal to

1

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- 1

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\frac{sin x}{x}

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\frac{x}{sin x}

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Solution

The correct option is A $1$
the given question turns in $= {lim}_{x \to 0} \frac{sin x}{2^{n} sin 2^{- n} x}$

$= \frac{x}{2^{n} 2^{- n} x}$
$= 1$

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Similar questions

lim x \to 0 cos \frac{x}{2} cos \frac{x}{2^{2}} cos \frac{x}{2^{3}} . . . . . . cos \frac{x}{2^{n}}

is equal to

$If cos (\frac{x}{2}) c o s (\frac{x}{2^{2}}) c o s (\frac{x}{2^{3}}) . . . . . . . . . . . . . . . t o \infty = \frac{s i n x}{x} t h e n \frac{1}{2^{2}} s e c^{2} (\frac{x}{2}) \frac{1}{2^{4}} s e c^{2} (\frac{x}{2^{2}}) + . . . . . . . =$

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equals to

Q. The value of

lim x \to 0 lim n \to \infty (cos \frac{x}{2} cos \frac{x}{2^{2}} cos \frac{x}{2^{3}} \dots cos \frac{x}{2^{n}})

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find

\frac{d y}{d x}

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limδx→0cosx2cosx22cosx23......cosx2n is equal to

The correct option is A 1the given question turns in =limx→0sinx2nsin2−nx =x2n2−nx =1

$lim δ x \to 0 cos \frac{x}{2} cos \frac{x}{2^{2}} cos \frac{x}{2^{3}} . . . . . . cos \frac{x}{2^{n}}$ is equal to

The correct option is A $1$
the given question turns in $= {lim}_{x \to 0} \frac{sin x}{2^{n} sin 2^{- n} x}$

$= \frac{x}{2^{n} 2^{- n} x}$
$= 1$