Question

$\underset{x\to 0}{lim}\frac{\sin x^0}{x}$ is equal to -

• A. 1
• B. $\pi$
• C. x
• D. $\frac{\pi }{180}$

Answer 1

The correct option is D $\frac{\pi }{180}$

$x^{\circ }=\frac{\pi x}{180}$

$\underset{x\to 0}{lim}\frac{\sin x^{\circ }}{x}=\underset{x\to 0}{lim}\frac{\sin \frac{\pi x}{180}}{x}=\frac{\pi }{180}$