wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

limxaxnanxa

Open in App
Solution

We know that
xnan=(xa)(xn1+axn2+....an1)

Hence,after putting the expansion in numerator.and applying limit.

limxaxnanxa=nan1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems on Integration
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon