Limx - -1 - cos xx2 -

lim_x → .1 cos xx^2( 00form) Using L' hospital Rule: #160; = lim_x → 0sin x2x = 12 ...

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Algebra of Limits

limx → .1 - c...

Question

$lim x \to . \frac{1 - cos x}{x^{2}} =$

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Solution

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