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Question

limxπ2(secxtanx)

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Solution

limxπ2(secxtanx)

limxπ2[1cosxsinxcosx]

limxπ2[1sinxcosx]

limxπ/2(cosxx2sinx2)2cos2x2sin2x2

{1=sin2dfracx2+cos2x/2,sinx=2sinx/2cosx/2,cosx=cos2x2sin2x2}

limxπ2(cosx/2sinx/2)2(cosx/2sinx/2)(cosx/2+sinx/2)

limxπ2cosx/2sinx/2cosx/2+sinx/2

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