$A$ nitrogenous fertilizers having more nitrogen is :

(N H_{4})_{2} S O_{4}

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C a (N O_{3})_{2}

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N H_{2} C O N H_{2}

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N H_{4} N O_{3}

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Solution

The correct option is C $N H_{2} C O N H_{2}$
Percentage of $N_{2}$ in following compounds is calculated by formula
$(a t o m i c w e i g h t o f N_{2} i n c o m p o u n d / A t o m i c w e i g h t t h e c o m p o u n d) \times 100$
So, percentage of $N_{2}$ in compounds is given as
In ${(N H_{4})}_{2} S O_{4}$ it is 21%
In $C a {(N O_{3})}_{2}$ it is 17%
In $N H_{2} C O N H_{2}$ it is 47%
In $N H_{4} N O_{3}$ it is 35%.

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Name the nitrogenous fertilizers .

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A nitrogenous fertilizers having more nitrogen is :

The correct option is C NH2CONH2Percentage of N2 in following compounds is calculated by formula (atomicweightofN2incompound/Atomicweightthecompound)×100So, percentage of N2 in compounds is given asIn (NH4)2SO4 it is 21%In Ca(NO3)2 it is 17%In NH2CONH2 it is 47%In NH4NO3 it is 35%.

$A$ nitrogenous fertilizers having more nitrogen is :