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Question

C2O27+I+H+Cr+3+l2+H2O
The equivalent weight of the reductant in the above equation is :- (At.wt. of Cr=52,I=127)

A
26
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B
127
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C
63.5
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D
36
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Solution

The correct option is D 36
+6Cr2O272Cr3+Reduction
Cr2O272Cr3++7H2O
Cr2O27+14H+2Cr3++7H2O
Cr2O27+14H++6e2Cr3++7H2O
(2II2+2e)3
6I3I2+6e
So, equivalent weight of Cr2O27=2166=36

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