$Calculate the number of molecules present in 0.25 moles of water (H_{2} O) .$

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Solution

$Number of molecules = Number of moles \times Avogadro' s number = 0.25 mol \times 6.022 \times 10^{23} molecules / mol = 1.505 \times 10^{23} molecules Therefore, the number of molecules present in 0.25 moles of water are 1.505 \times 10^{23} .$

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Calculatethenumberofmoleculespresentin0.25molesofwater(H2O).

Numberofmolecules=Numberofmoles×Avogadro'snumber=0.25mol×6.022×1023molecules/mol=1.505×1023moleculesTherefore,thenumberofmoleculespresentin0.25molesofwaterare1.505×1023.

$Calculate the number of molecules present in 0.25 moles of water (H_{2} O) .$

$Number of molecules = Number of moles \times Avogadro' s number = 0.25 mol \times 6.022 \times 10^{23} molecules / mol = 1.505 \times 10^{23} molecules Therefore, the number of molecules present in 0.25 moles of water are 1.505 \times 10^{23} .$