Question

${\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{NaHCO}}_3\to {\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{H}}_2\mathrm{O}+{\mathrm{CO}}_2$

The above reaction can be best confirmed by observing :

• A. Precipitate formation
• B. Bubble formation
• C. Colour change
• D. Temperature change

Answer 1

The correct option is B

Bubble formation

Explanation for the correct option:

1. The above given reaction, $$\begin{gathered} {\mathrm{CH}}_3\mathrm{COOH}\left(\mathrm{aq}\right)+{\mathrm{NaHCO}}_3\left(\mathrm{s}\right)\to {\mathrm{CH}}_3\mathrm{COONa}\left(\mathrm{aq}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)+{\mathrm{CO}}_2\left(\mathrm{g}\right)\uparrow \\ (\mathrm{Acetic}\mathrm{acid})(\mathrm{Sodium}\mathrm{bicarbonate})(\mathrm{Sodium}\mathrm{acetate})\left(\mathrm{Water}\right)(\mathrm{Carbon}\mathrm{dioxide}) \end{gathered}$$, Sodium bicarbonate $\left({\mathrm{NaHCO}}_3\right)$ reacts with Acetic acid $\left({\mathrm{CH}}_3\mathrm{COOH}\right)$to give Sodium acetate $\left({\mathrm{CH}}_3\mathrm{COONa}\right)$, Water$\left({\mathrm{H}}_2\mathrm{O}\right)$ and Carbon dioxide $\left({\mathrm{CO}}_2\right)$ gas is evolved.
2. This is a neutralization reaction, where the formation of salt is seen, and Carbon dioxide $\left({\mathrm{CO}}_2\right)$ is evolved which gives brisk effervescence, which is colorless and odorless.

Explanation for the incorrect options:

1. A reaction in which two ionic compounds react to form an insoluble salt (precipitate) is termed as Precipitation reaction. In this reaction there is no formation of precipitation is seen. So, option (A) is incorrect.
2. In this reaction no color change is observed, therefore option (C) is also incorrect.
3. Also there is no temperature change is observed in this reaction, so option (D) is also incorrect.

Hence, option (B) is correct i.e., bubble formation is seen.