$f (x) = 25 + | x - 9 |$ is increasing in

(- \infty, 9)

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(9, \infty)

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(- \infty, \infty)

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\emptyset

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Solution

The correct option is B $(9, \infty)$
$f (x) = {\begin{matrix} 16 + x & x > 9 34 - x & x < 9 \end{matrix}$
$= {\begin{matrix} 1 & x > 9 - 1 & x < 9 \end{matrix}$
$f^{1} (x) > 0$
when $x > 9$

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Similar questions

f (x) = 25 + | x - 9 |

25 x^{2} - 9

f (9) = 9, f^{'} (9) = 4, lim x \to 9 \frac{\sqrt{f (x)} - 3}{\sqrt{x} - 3} =

lim x \to 9 \frac{\sqrt{f (x)} - 3}{\sqrt{x} - 3}

f (x) = k x^{3} - 9 x^{2} + 9 x + 3

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