${I f}^{35} C_{n + 7} =^{35} C_{4 n - 2},$ then write the values of $n$

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Solution

$^{35} C_{n + 7} =^{35} C_{4 n - 2}$

$^{n} C_{r}$ = $^{n} C_{n - r}$
$∴$ n+7+4n-2=35

5n+5=35
5n=30

$\Rightarrow n = 6$

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