Question

$(N{H}_4{)}_{2}C{r}_2{O}_7$ on heating gives a gas which is also given by:

• A. heating $N{H}_{4}N{O}_2$
• B. heating $N{H}_{4}N{O}_3$
• C. $M{g}_3{N}_2+H_{2}O$
• D. $Na(comp.)+H_2{O}_2$

Answer 1

Answer: (A)

heating $N{H}_{4}N{O}_2$

$\left(N{H}_4\right){}_{2}C{r}_2{O}_7\stackrel{\Delta }{\to }{N}_2\uparrow +C{r}_2{O}_3+4H_{2}O$
$N{H}_{4}N{O}_2\stackrel{\Delta }{\to }{N}_2\uparrow +2H_{2}O$
Therefore, the answer is ammonium nitrate.