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Work-Energy Theorem

O is the cent...

Question

$O$ is the centre of an equilateral triangle $A B C . F_{1}, F_{2}$ and $F_{3}$ are three forces acting along the sides $A B, B C$ and $A C$ as shown. What should be the magnitudes of $F_{3}$ so that the total torque about $O$ is zero.

\frac{F_{1} + F_{2}}{2}

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F_{1} - F_{2}

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F_{1} + F_{2}

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2 (F_{1} + F_{2})

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Solution

The correct option is C $F_{1} + F_{2}$
We know that torque is given by ,
$\to τ = \to r X \to F$
Therefore torque due to F1 and F2 are out of the plane whereas torque due to F3 goes inside the plane.
For the torques to cancel, $F_{3} = F_{1} + F_{2}$

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O is the centre of an equilateral triangle ABC. F1, F2 and F3 are three forces acting along the sides AB, BC and AC as shown. What should be the magnitudes of F3 so that the total torque about O is zero.

The correct option is C F1+F2 We know that torque is given by ,→τ=→rX→FTherefore torque due to F1 and F2 are out of the plane whereas torque due to F3 goes inside the plane.For the torques to cancel, F3=F1+F2

$O$ is the centre of an equilateral triangle $A B C . F_{1}, F_{2}$ and $F_{3}$ are three forces acting along the sides $A B, B C$ and $A C$ as shown. What should be the magnitudes of $F_{3}$ so that the total torque about $O$ is zero.

The correct option is C $F_{1} + F_{2}$
We know that torque is given by ,
$\to τ = \to r X \to F$
Therefore torque due to F1 and F2 are out of the plane whereas torque due to F3 goes inside the plane.
For the torques to cancel, $F_{3} = F_{1} + F_{2}$