$P {C l}_{3}$ on hydrolysis gives :

H_{3} P O_{4}

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H_{3} P O_{3}

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P O C

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H_{3} P O_{2}

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Solution

The correct option is B $H_{3} P O_{3}$
$P C l_{3} + 3 H_{2} O \to H_{3} P O_{3} + 3 H C l$

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