TP,TQ are tangents to a parabola y2=4ax,p1,p2,p3 are the lengths of the perpendicular from P,T,Q respectively on tangent at the vertex, then p1,p2,p3 are in
A
A.P.
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B
G.P.
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C
H.P.
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D
A.G.P.
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Solution
The correct option is B G.P. Eq. of tangent through T(h.k) is ky=2a(x+h) y=2a(x+h)k 4a2(x+h)2k2=4ax a(x2+h2+2hx)=k2x p1p2=x1x2 x1x2=h2 ∴x1,h,x2 are in G.P.