Question

Max makes a rectangle on a piece of paper. The length and width of the rectangle is 9 units and 8 units, respectively. He wants to fit a square inside the rectangle. What is the area of the biggest square that can fit inside?

Answer 1

● Length of the rectangle = 9 units
● Width of the rectangle = 8 units
● Area of a rectangle = Length $\times$ Width
● Area of the rectangle = 9 $\times$ 8 sq units
● Area of the rectangle = 72 sq units
● The maximum length of the square should be equal to the width of the rectangle.
● The area of the square of side 8 units is the maximum area of the square that can fit inside this rectangle.
● Area of square = Side $\times$ Side
● So, the maximum area of the square can be,
● Area = 8 $\times$ 8 sq units
● Area = 64 square units

Hence, option D is correct.