Question

Maximise Z = 3x + 2y

subject to.

Answer 1

The feasible region determined by the constraints, x + 2y ≤ 10, 3x + y ≤ 15, x ≥ 0, and y ≥ 0, is as follows.

The corner points of the feasible region are A (5, 0), B (4, 3), and C (0, 5).

The values of Z at these corner points are as follows.

Corner point	Z = 3x + 2y
A(5, 0)	15
B(4, 3)	18	→ Maximum
C(0, 5)	10

Therefore, the maximum value of Z is 18 at the point (4, 3).