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Question

Maximise Z=3x+2y
subject to x+2y10,3x+y15,x,y0

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Solution

The feasible region determined by the constraints x+2y10,3x+y15,x,y0 is as shown.
The corner points of the feasible region are A(5,0),B(4,3) and C(0,5).
The values of Z at these corner points are as follows.
Corner points Z=3x+2y
A(5,0) 15
B(4,3)18 Maximum
C(0,5)10
Therefore, the maximum value of Z is 18 at the point (4,3)
386365_422926_ans.PNG

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