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Question

Maximise Z = 5x + 3y

subject to.

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Solution

The feasible region determined by the system of constraints, 3x + 5y ≤ 15,

5x + 2y ≤ 10, x ≥ 0, and y ≥ 0, are as follows.

The corner points of the feasible region are O (0, 0), A (2, 0), B (0, 3), and .

The values of Z at these corner points are as follows.

Corner point

Z = 5x + 3y

0(0, 0)

0

A(2, 0)

10

B(0, 3)

9

→ Maximum

Therefore, the maximum value of Z is


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