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Byju's Answer
Standard XII
Mathematics
Law of Reciprocal
Maximise Z=...
Question
Maximise
Z
=
x
+
y
, subject to
x
−
y
≤
−
1
,
x
−
y
≥
0
,
x
,
y
≥
0
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Solution
The region determined by the constraints
Z
=
x
+
y
, subject to
x
−
y
≤
−
1
,
x
−
y
≥
0
,
x
,
y
≥
0
is as shown.
There is no feasible region and thus,
Z
has no maximum value.
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