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Question

Maximize:Z=x+2y
Subject to the constraints:x+2y100,2xy0,2x+y200,x0,y0
Solve the L.P.P. graphically.

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Solution

To Maximize:Z=x+2y

Subject to : x+2y100,2xy0,2x+y200,x0,y0

Corner PointsValue of ZA(0,200)400Max.valueB(50,100)250C(20,40)100D(0,50)100
Clearly,Maximum value of Z=400 at A(0,200).


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