Maximize:Z=x+2y
Subject to the constraints:x+2y≥100,2x−y≤0,2x+y≤200,x≥0,y≥0
Solve the L.P.P. graphically.
To Maximize:Z=x+2y
Subject to : x+2y≥100,2x−y≤0,2x+y≤200,x≥0,y≥0
Corner PointsValue of ZA(0,200)400←Max.valueB(50,100)250C(20,40)100D(0,50)100
Clearly,Maximum value of Z=400 at A(0,200).