Maximum bond angle is present in:

B B r_{3}

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{B C l}_{3}

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{B F}_{3}

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none of these

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Solution

The correct option is A $B B r_{3}$
Boron halides show $s p 2$ hybridisation but due to electronegativity difference between halides, the bond angle will show variations
Bond anvle of any molecule is inverely proportional to the electronegativity of surrounding atoms i.e., lesser the electronegativity of attached atoms than more is the bond angle
So the order of electronegativity of halides are
$F > C l > B r$
$∴$ order of bond angle is $B {B r}_{3} > B {C l}_{3} > B F_{3}$
Ans is $B {B r}_{3}$

Suggest Corrections

Similar questions

{B l}_{3} < {B B r}_{3} < {B F}_{3} < {B C l}_{3}

The correct order of Lewis acidity of $B X_{3}$ molecule is

B F_{3} < B C l_{3} < B B r_{3} < B I_{3}

B F_{3}, B C l_{3}, B B r_{3}, B I_{3}

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