Maximum covalent character is in:

N a I

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M g I_{2}

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{A l C l}_{3}

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{A l I}_{3}

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Solution

The correct option is D $N a I$
Due to large size of $N a^{+}$ and $I^{-}$ among all $e^{-}$ attracting tendency is less. Hence have maximum covalent. As $N a^{+}$ has polarizing power to polarize one $I^{-}$ ion.

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N a C l, M g C l_{2}, A l C l_{3}

N a C l, M g {C l}_{2}, A l {C l}_{3}

A l {C l}_{3} < M g {C l}_{2} < N a C l

Maximum covalent character is associated with the compound

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