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Question

Maximum data rate to transmit binary signal from Nyquist theorem is

A
2H
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B
3H
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C
0
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D
1
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Solution

The correct option is C 2H

Maximum data rate to transmit binary signal from Nyquist theorem is 2H.

Nyquist's Theorem - If the signal has V discrete levels over a transmission medium of bandwidth H, the maximum data rate = 2H log2 V bits/sec. A noiseless 3-kHz channel cannot transmit binary signals at a rate exceeding 6000 bps (= 2 x 3000 log2 2). Workspace.

Nyquist bit rate formula defines the theoretical maximum bit rate. r = 2 X B X log2 L. In this formula, B is the bandwidth of the channel, L is the number of signal levels used to represent data, and r is the bit rate in bits per second.

Data rates are often measured in megabits (million bits) or megabytes (million bytes) per second.



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