Question

Maximum fluctuation of kinetic energy in an engine has been calculated to be 2600 J. Assuming that the engine runs at an average speed of 200 rpm, the polar mass moment of inertia ($inkg.m^2$) of flywheel to keep the speed fluctuation within $\pm 0.5$% of the average speed is

• A. 592.73

Answer 1

The correct option is A 592.73
$\Delta E=2600J,N_{average}=200rpm,I=?$

$C_s=\pm 0.5\%=1\%=\frac{1}{100}=0.01$

$\Delta E=I{\omega }^2{C}_s$

$2600=I\times {\{\frac{2\pi }{60}\times 200\}}^2\times 0.01$

$2600=I\times 438.6491\times 0.01$

$I=\frac{2600}{4.3865}=592.73kg{m}^2$