Maximum number of unpaired electrons are present in:

^{+ 2}

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^{+ 3}

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^{+ 3}

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^{+ 2}

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Solution

The correct option is D Mn $^{+ 2}$
$T i^{+ 2}$ - $[A r] 3 d^{2}$
$S c^{+ 3}$ - $[A r]$
$C r^{+ 3}$ - $[A r] 3 d^{3}$
$M n^{+ 2}$ - $[A r] 3 d^{5}$
So, $M n^{+ 2}$ have maximum number of unpaired electrons viz.5

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