Maximum ordinate of ILD for force in member $U_{3} U_{4}$ in the truss shown below is

\frac{9}{4}

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\frac{9}{8}

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\frac{9}{2}

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1.0

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Solution

The correct option is B $\frac{9}{8}$
$U_{3} U_{4}$ member is a compression member,

$H e i g h t o f I L D = \frac{a (l - a)}{l h}$ $(C o r r e s p o n d i n g t o t h e j o i n t L_{4}$ )

$= \frac{9 \times 9}{18 \times 4} = \frac{9}{8}$

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