Maximum oxidation state exhibited by osmium is:

+ 8

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+ 7

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+ 6

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+ 5

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Solution

The correct option is A $+ 8$
Osmium - $[X e] 4 f^{14} 5 d^{6} 6 s^{2}$ .
It can lose 8 electrons to form +8 oxidation state. In $O s O_{4}$ , Osmium shows +8 oxidation state.

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The maximum oxidation state of osmium is:

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