Question

Maximum pressure rise due to water hammer in a pipeline$a=\text{area of the pipe};V_0=\text{Velocity,}g=\text{acceleration due to gravity};t=\text{time period;}L=\text{length of the pipeline) is}$

• A. $\frac{a{V}_0}{2g}$
• B. $\frac{a{V}_0^2}{2g}$
• C. $\frac{L{V}_0}{gt}$
• D. Independent of the dimensions of the pipe

Answer 1

The correct option is C $\frac{L{V}_0}{gt}$

For instantaneous closure of valve, the pressure head at valve end is

$\Delta h=\frac{C{V}_0}{g}$

Time period for travel of pressure wave from one end to the other is

$t=\frac{L}{C}$

Therefore velocity of pressure wave

$C=\frac{L}{t}$

$\text{and}\Delta h=\frac{L{V}_0}{gt}$