Question

The maximum spin only magnetic moment for transition metal complex may be

• A. $5.92BM$
• B. $6.92BM$
• C. $4.89BM$
• D. $3.87BM$

Answer 1

The correct option is A

$5.92BM$

Step 1. Given data:

The transition is for the metal complex.

Step 2. Formula used:

The spin only magnetic moment $\mu$ in $BM$,

$\mu =\sqrt{n\left(n+2\right)}$ ($n=$Number of unpaired electrons, $BM=$Bohr magneton)

The magnetic moment is the magnetic strength or the orientation of any magnet that can produce a magnetic field like an electromagnet.

Step 3. Calculating spin only magnetic moment

The highest value of $n$ in transition metal complex is $5$ in its $d^5$ configuration.

$$\begin{gathered} \begin{array}{rcl}n& =& 5\\ & \Rightarrow & \mu =\sqrt{5\left(5+2\right)}\\ & =& \sqrt{35}\end{array} \\ =5·916BM \\ =5·92BM \end{gathered}$$

Thus, the maximum spin-only magnetic moment for the transition metal complex is $5·92BM$

Hence, option A is the correct answer.