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Question

Maximum value of 1x is infinity and minimum value is negative infinity. So the range of 1x is (-infinity, infinity)


A

True

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B

False

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Solution

The correct option is B

False


The graph of 1x is

The graph never touches y = 0, so 0 is not in range of the function y = 1x. Additionally infinity is always non inclusive. So a closed bracket will never be adjacent to infinity or minus infinity.

So the correct range would be (-infinity,0) (0,infinity).

The given statement is false


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