Maximum value of 1x is infinity and minimum value is negative infinity. So the range of 1x is (-infinity, infinity)
False
The graph of 1x is
The graph never touches y = 0, so 0 is not in range of the function y = 1x. Additionally infinity is always non inclusive. So a closed bracket will never be adjacent to infinity or minus infinity.
So the correct range would be (-infinity,0) ∪ (0,infinity).
⇒The given statement is false