Given that MB bisects ∠CBA and NB bisects ∠ABD.
So, ∠ABM=1/2 of ∠CBA and ∠ABN=1/2 of ∠ABD.
∠MBN= ∠ABM + ∠ABN
∠MBN=1/2 of ∠CBA+ 1/2 of ∠ABD
∠MBN=1/2 {∠CBA+∠ABD)
∠MBN=1/2 {∠CBD}
∠MBN=1/2 {180⁰} (Linear pair)
∠MBN=90⁰.
Therefore, the value of ∠MBN is 90⁰.