MCQ - sin sin -1 5- 6 -cos -1 cos 5- 3 - tan -1 tan 7- 3

The correct option is B 5π 6 Given #160; sin ^ 1(sin(5π6)) +cos ^ 1(cos(5π3))+tan ^ 1(tan(7π3 )) sin ^ 1(sin( π π6)) +cos ^ 1(cos( 2π π 3))+t ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Domain and Range of Basic Inverse Trigonometric Functions

MCQ : sin s...

Question

$M C Q : s i n ({s i n}^{- 1} \frac{5 π}{6}) + c o s^{- 1} (c o s \frac{5 π}{3}) + {t a n}^{- 1} (t a n \frac{7 π}{3})$

\frac{5 π}{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{π}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{7 π}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{29 π}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

∣ ∣ ∣ 1 - \frac{| sin x |}{1 + | sin x |} ∣ ∣ ∣ \geq \frac{2}{3}

x

$c o s^{- 1} (c o s \frac{7 π}{6})$ is equal to
a) $\frac{7 π}{6}$
b) $\frac{5 π}{6}$
c) $\frac{π}{3}$
d) $\frac{π}{6}$

The polar form of $\frac{- \sqrt{3}}{2} - \frac{i}{2}$ (where i = $\sqrt{- 1}$ ) is

{(\frac{5 π}{12})}^{\circ}

- {(\frac{7 π}{12})}^{\circ}

\frac{π}{3}

\frac{5 π^{\circ}}{6}

\frac{2 π^{\circ}}{9}

\frac{7 π^{\circ}}{24}

If the product of the roots of equation 2 $x^{2}$ + ax + 4 sin a = 0 is 1, then roots will be imaginary if :

Join BYJU'S Learning Program