M 22 SiCl 2 on hydrolysis in presence of Cu at 570 K will produce-A- Me 2 Si OH 2B- Me 2 Si - OC- - O - Me 2 Si - O - nD- Me 2 SiCl OH

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Reaction with Diazonium Salts

M 22 SiCl 2 o...

Question

$M e_{2} S i C l_{2}$ on hydrolysis in presence of Cu at 570 K will produce:

(M e)_{2} S i (O H)_{2}

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(M e)_{2} S i = O

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[- O - (M e)_{2} S i - O -]_{n}

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M e_{2} S i C l (O H)

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Solution

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(M e)_{2} S i C l_{2}

$M e_{2} S i C l_{2}$ on hydrolysis will produce

(C H_{3})_{2} S i C l_{2}

V

0.1 M Z n S O_{4}

0.01 M C u S O_{4}

(E_{{C u}^{2 +} / C u}^{o} = 0.34 V; E_{{Z n}^{2 -} / Z n}^{o} = - 0.76 V)

300^{o} C

C u

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