Me2CH-OH-CH-MeABProduct B of above reaction -

The correct option is A Me_2C(OH)CH_2Me As refer to the above image first #10;dehydration with Al_2O_3 takes place followed by addition. ...

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Preparation of Alcohols from Grignard Reagents

Me2CH-OH|CH-M...

Question

$M e_{2} C H - C | H O H - M e A l_{2} O_{3} - -- \to 350^{\circ} (A) (I) H I - ----- \to (I I) A g O H (B)$
Product (B) of above reaction :

M e_{2} C (O H) C H_{2} M e

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M e_{2} C H - C H | O H - M e

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M e - C H | O H - C M e_{3}

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H O - C H_{2} - (C H_{2}) M e

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M e_{3} C - O - C H_{2} C H_{3} + H I 1 mole Δ ⟶

M e_{3} C - O - C H_{2} C H_{3} + H I (1 mole) Δ - \to

C H_{3} - C H = C H - C H_{2} - O H P C C - -- \to

(I) {M e}_{3} C - C l ⊖ O H - - \to {M e}_{3} C - O H

(I I) F_{3} C - C H | M e - C l ⊖ O H - - \to F_{3} C - C H | M e - O H

(I I I) {M e}_{3} C - C l 90 % D_{2} O + 10 % e t h e r - ----------- \to {M e}_{3} C - O D

(I V) {M e}_{3} C - C l 90 % D_{2} O + 10 % e t h e r - ----------- \to {M e}_{3} C - O H

H O - C H_{2} - C | H O H - C H_{2} - O H

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