$M e_{2} S i C l_{2}$ on hydrolysis produces:

M e_{2} S i (O H)_{2}

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M e_{2} S i = O

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(- O - M e_{2} S i - O -)_{n}

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M e_{2} S i C l (O H)

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Solution

The correct option is D $(- O - M e_{2} S i - O -)_{n}$
$M e_{2} S i C l_{2} ⟶ M e_{2} S i (O H)_{2} ⟶ + M e_{2} S i + H_{2} O$
replacement of $C l$ group with $O H^{-}$ and spontaneous formation of $H^{+} C l^{-}$
$M e_{2} S i = 0$

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