Question

$M{e}_{2}SiC{l}_2$ on hydrolysis will produce

• A. $M{e}_{2}Si(OH{)}_2$
• B. $M{e}_{2}SiO$
• C. $[-O-M{e}_{2}Si-O-{]}_n$
• D. $M{e}_{2}SiClOH$

Answer 1

The correct option is C

$[-O-M{e}_{2}Si-O-{]}_n$

To start with,

$M{e}_{2}SiC{l}_2+2H_{2}O⟶M{e}_{2}Si(OH{)}_2$

The product polymerizes to yield

$[-O-M{e}_{2}Si-O-{]}_n$