${M e}_{3} C - M g C l$ on reaction with $D_{2} O$ produces:

{M e}_{3} C D

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{M e}_{3} C O D

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{(C D)}_{3} C D

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{(C D)}_{3} C O D

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Solution

The correct option is A ${M e}_{3} C D$
Hence the answer is option A.

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