Me - C - C - Me Na - NH 3 liq - EtOH -33- C X - dil-alkaline KMnO 4-Product s The products from the above reaction will beA-B-C-D-

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Order of Reaction

Me - C ≡ C - ...

Question

$M e - C \equiv C - M e N a / N H_{3} (l i q .) - ------- \to E t O H, - 33^{\circ} C X = d i l . a l k a l i n e K M n O_{4} - ----------- \to$ Product(s)
The product(s) from the above reaction will be

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