Question

Mean deviation for 𝑛 observations $x_1,x_2\dots \dots x_n$ from their mean $\overline{x}$ is given by

• A. ${\sum }_{i=1}^n{(x_i-\overline{x})}^2$
• B. $\frac{1}{n}{\sum }_{i=1}^n|x_i-\overline{x}|$
• C. $\frac{1}{n}{\sum }_{i=1}^n{(x_i-\overline{x})}^2$
• D. ${\sum }_{i=1}^n|x_i-\overline{x}|$

Answer 1

The correct option is B $\frac{1}{n}{\sum }_{i=1}^n|x_i-\overline{x}|$

Mean deviation for 𝑛 observations $x_1{x}_2,\dots ,x_n$ from their mean is

M.D.$\frac{1}{n}{\sum }_{i=1}^n|x_i-\overline{x}|$

Hence, the correct option is (𝐵)