Mean deviation from median of the data $90, 100, 125, 115, 110$ is?

10

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20

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30

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None of these

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Solution

The correct option is A $10$
Arranged in ascending order $90, 100, 110, 115, 125$
$N = 5$ odd
Median $= (\frac{N + 1}{2})^{t h}$ term $= 3^{r d}$ term $= 110$
So, mean deviation $= \frac{\sum | x_{i} - N |}{N} = \frac{20 + 10 + 0 + 5 + 15}{5} = 10$

Suggest Corrections

$x$	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
$f$	$5$	$8$	$15$	$16$	$6$

$x$	$10$	$20$	$30$	$40$	$50$	$60$
$f$	$9$	$18$	$25$	$27$	$14$	$7$

$C I$	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$
$f$	$5$	$12$	$3$	$11$	$9$

Class	0 - 10	10 - 20	20 - 30	30 - 40	40 - 50	50 - 60	60 - 70	70 - 80
frequency	5	8	7	12	28	20	10	10