Mean of $25$ observations was given as $78.4$ . Later it was found out that $96$ was misread as $69$ . Find the correct mean.

79.84

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79.48

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79.54

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79.45

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Solution

The correct option is A $79.48$
$n = 25$
$u = 78.4$ (initial wrong mean)
$\sum x = n \times u = 25 \times 78.4 = 1960$
Now $69$ was read as $96$ , so
True $\sum x = 1960 - 96 + 69 = 1987$
$∴ u^{'} = \frac{1987}{25}$
Thus $u^{'} = 79.48$
Ans- Option B

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Question 12
Mean of 50 observations was found to be 80.4. But later on, it was discovered that 96 was misread as 69 at one place. Find the correct mean.

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Q. The mean of 100 observations was calculated as 40 It was found later on that one of the observations was misread as 83 instead of 53 The correct means is

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Mean of 25 observations was given as 78.4. Later it was found out that 96 was misread as 69. Find the correct mean.

The correct option is A 79.48n=25u=78.4 (initial wrong mean)∑x=n×u=25×78.4=1960Now 69 was read as 96, soTrue ∑x=1960−96+69=1987∴u′=198725Thus u′=79.48Ans- Option B

Mean of $25$ observations was given as $78.4$ . Later it was found out that $96$ was misread as $69$ . Find the correct mean.

The correct option is A $79.48$
$n = 25$
$u = 78.4$ (initial wrong mean)
$\sum x = n \times u = 25 \times 78.4 = 1960$
Now $69$ was read as $96$ , so
True $\sum x = 1960 - 96 + 69 = 1987$
$∴ u^{'} = \frac{1987}{25}$
Thus $u^{'} = 79.48$
Ans- Option B