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Arithmetic Mean and Range

Mean of 41,...

Question

Mean of $41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 49, 42, 52, 60 i s 54.8$

A

True

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B

False

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C

Neither

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D

None

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Solution

The correct option is A False
$M e a n$ $=$ $\frac{s u m o f a l l n u m b e r s}{n o . o f n u m b e r s}$
$∴$ $m e a n$ $=$ $\frac{41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 49 + 42 + 52 + 60}{15}$ $=$ $55.4$

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