Mean of 5 observations is 3. If four of these observations are 4, 5, 1, 3 and one is missing, then variance of all five observations is
A
4
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B
2
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C
2.5
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D
3
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Solution
The correct option is B 2 Givne 4+5+1+3+x5=3 ⇒13+x=15⇒x=2 ∴ Observation are 1, 2, 3, 4, 5 Variance of first n natural numbers =n2−112, by taking n =5 variance =25−112=2